1.) For 0.100 M of weak acid (propanoic acid HPr) the Kais given by 1.30 x10 -5

Question

1.) For 0.100 M of weak acid (propanoic acid HPr) the Kais given by 1.30 x10-5 , calculate the pH ofthe sample. 2.) For 0.250 M of weak acid (NaHS) the Kb is given by 1.22x10-13 , calculate the pH of the weak base. 1.) For 0.100 M of weak acid (propanoic acid HPr) the Kais given by 1.30 x10-5 , calculate the pH ofthe sample. 2.) For 0.250 M of weak acid (NaHS) the Kb is given by 1.22x10-13 , calculate the pH of the weak base. 2.) For 0.250 M of weak acid (NaHS) the Kb is given by 1.22x10-13 , calculate the pH of the weak base.

Explanation / Answer

1. The first thing we need to do is write the equation: HPr + H2O---> H3O+ +Pr- Now, we set up an ICE chart. HPr + H2O---> H3O+ +Pr- 0.1M     0       0 -x          +x      +x 0.1-x       x       x Ka = (H+)(Pr-)/(HPr) 1.30 x10-5= x2/0.1-x Note: We canignore the change because 0.1/Ka > 400. Rearrange for x, x=0.1 x 1.30 x10-5 x=0.0011 x= [H3O+] pH=-log[H3O+]=-log[0.0011]=2.96 Hope this helps!

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