A mixture at 827 degrees celsius in a fixed volume containercontains 0.552 moles

Question

A mixture at 827 degrees celsius in a fixed volume containercontains 0.552 moles CO2, 0.552 moles of H2, 0.448 moles of CO, and0.448 moles of H2O. Calculate Qc for this reaction.    CO2 (g) + H2 (g)-->CO (g)+ H2O (g)                               <-- A mixture at 827 degrees celsius in a fixed volume containercontains 0.552 moles CO2, 0.552 moles of H2, 0.448 moles of CO, and0.448 moles of H2O. Calculate Qc for this reaction.    CO2 (g) + H2 (g)-->CO (g)+ H2O (g)                               <--

Explanation / Answer

ive never seen this kind of question before, but i would just work through it like any other problem. The volumes should cancel out

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