1. What is the frequency (in Hz or sec - 1 ) ofelectromagnetic radiation that ha
ID: 680457 • Letter: 1
Question
1. What is the frequency (in Hz or sec-1) ofelectromagnetic radiation that has a wavelength of 1.23 x10-6 cm?
(A) 2.44 × 1016
(B) 2.44 × 1014
(C) 3.68 × 104
(D) 3.68 × 102
(E) 4.10 × 10-15
2. Which of the following transitions in the Bohr hydrogen atomprovides the absorption of thehighest energy photon?
(A) n=9 ® n=1
(B) n=1 ® n=9
(C) n=3 ® n=6
(D) n=6 ® n=3
(E) n=12 ® n=1
3. An electron has a mass of 9.1 x 10-31 kg and an deBroglie wavelength of
8.7 x 10-11 m. What is its velocity (in m/s)?
(A) 8.4 × 103
(B) 1.2 × 10-7
(C) 6.9 × 10-5
(D) 8.4 × 106
(E) 8.4 × 10-3
4. What is H for the ionization of exactly one mole of hydrogenatoms?
(A) +2.18 x 10-21 J
(B) -2.18 x 10-21 J
(C) +1.31 x 103 kJ
(D) -1.31 x 103 kJ
(E) None of the other answers are within 50% of the correct value
5. Which of the following sets of quantum numbers (n,l, ml, ms)represents an acceptable set for an electron in a hydrogenatom?
(A) 2, 2, -1, -1/2
(B) 1, 0, 0, +1/2
(C) 3, 2, 3, +1/2
(D) 5, 4, -5, -1/2
(E) 5, 4, -3, +3/2
explain theanswers
Explanation / Answer
wavelength = 1.23 x 10-6 cm = 1.23 * 10 ^ -8 m So, frequency f = c / where c = speed of light = 3 * 10 ^ 8 m / s So, f = 2.439 * 10 ^ 16 Hz (2).option ( B ) is correct (3).electron mass m = 9.1 x 10-31kg de Broglie wavelength = 8.7 x10-11 m we know = h / m v from this speed v = h / m where h = planck's constant = 6.625 * 10 ^ -34 J s m= mass = 9.1 * 10 ^ -31 kg subsitue values we get v = 83.68 * 10 ^ 5 m /sRelated Questions
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