is there a rule for when the o2\'s cancel out to make justone ...what do you do

Question

is there a rule for when the o2's cancel out to make justone ...what do you do to the enthalpy? i keep getting the wrong answer Given the following data:
C(s) + 2H2(g) ® CH4(g) H = -74.8 kJ CO2(g) ®C(s) + O2(g) H = +393.5 kJ CH4(g) + 2O2(g) ®CO2(g) + 2H2O(l) H = -890.3 kJ
Find the H of the following reaction:
2H2O(l) ®2H2(g) + O2(g)

is there a rule for when the o2's cancel out to make justone ...what do you do to the enthalpy? i keep getting the wrong answer Given the following data:
C(s) + 2H2(g) ® CH4(g) H = -74.8 kJ CO2(g) ®C(s) + O2(g) H = +393.5 kJ CH4(g) + 2O2(g) ®CO2(g) + 2H2O(l) H = -890.3 kJ

Explanation / Answer

it says that answer is wrong

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