what is the hydroxide ion concentration of an aqueous 0.00370Mcaffeine solution?

Question

what is the hydroxide ion concentration of an aqueous 0.00370Mcaffeine solution? The most basic nitrogen atom in caffeine has aKb of 4.1x10-4 I found the equation to be: C8H10N4O2(aq) +H2O(l)C8H10N4O2H+(aq)+ OH- what is the hydroxide ion concentration of an aqueous 0.00370Mcaffeine solution? The most basic nitrogen atom in caffeine has aKb of 4.1x10-4 I found the equation to be: C8H10N4O2(aq) +H2O(l)C8H10N4O2H+(aq)+ OH-

Explanation / Answer

Setup an ICE table to solve this problem. Kb = (x^2)/(0.00370 - x) ---> 4.1 * 10-4 =x^2/(0.00370) (4.1 * 10-4)(0.00370) = x^2 ----> x = (4.1 *10-4)(0.00370) x = .00123 M concentration. [OH-] = (1.0 * 10^-14)/(.00123) = 8.13e-12 M (The pHshould be 11, which should be reasonable since you're finding[OH-] concentration.) I hope this helps.

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