if 75 ml of an agno3 solution reacts with enough cu to produce .25 ag by single

Question

if 75 ml of an agno3 solution reacts with enough cu to produce .25 ag by single displacement what is molarity of initial agn03 solution if copper nitrate is other product

Explanation / Answer

AgNO3 + Cu --> Ag +CuNO3 AgNO3 = 169.8 g/mol Ag = 107.8 g/mol From the equation, the ratio between AgNO3 and Ag is 1 to 1(Looking at the coefficients in front of AgNO3 and Ag) In the equation .25 g of Ag were yielded so divide .25g by107.8g/mol to find the number of moles this is.     = .0023 moles of Ag This means we also have .0023 moles of AgNO3 in 75 mL, to findmolarity we need to convert mL to L and get .075L. Now divide.0023 moles by .075L to find the molarity which is .031M

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