the following equilibrium constants were determined at 1123K: C (s)+ CO 2 (g) 2C
ID: 678773 • Letter: T
Question
the following equilibrium constants were determined at 1123K: C (s)+ CO2(g) 2CO(g) K'p= 1.3 * 1014 CO (g)+ Cl2(g) COCl2(g) K''p=6.00*10-3 a) Calculate the equilibrium constant at 1123 K for thereaction: C(s)+ CO2(g)+ 2 Cl2(g) 2COCl2(g) b) Write the equilibrium constant expression, Kp ?Write the pressure in the following formate: (PCO) the following equilibrium constants were determined at 1123K: C (s)+ CO2(g) 2CO(g) K'p= 1.3 * 1014 CO (g)+ Cl2(g) COCl2(g) K''p=6.00*10-3 a) Calculate the equilibrium constant at 1123 K for thereaction: C(s)+ CO2(g)+ 2 Cl2(g) 2COCl2(g) b) Write the equilibrium constant expression, Kp ?Write the pressure in the following formate: (PCO) a) Calculate the equilibrium constant at 1123 K for thereaction: C(s)+ CO2(g)+ 2 Cl2(g) 2COCl2(g) b) Write the equilibrium constant expression, Kp ?Write the pressure in the following formate: (PCO)Explanation / Answer
C (s)+ CO2(g) 2CO(g) K'p= 1.3 * 1014 Multipling with 2 to the equation 2 , 2 CO (g)+ 2Cl2(g) 2COCl2(g) K''p= 36 * 10 ^ -6 Now adding the two equations , C(s) + CO2(g) + 2Cl2(g) 2 COCl2(g) K = 46.8 * 10 ^ 8 = 4.68 * 10 ^ 9 b) Kp =P2 COCl2 / P2Cl2PCO2 Multipling with 2 to the equation 2 , 2 CO (g)+ 2Cl2(g) 2COCl2(g) K''p= 36 * 10 ^ -6 Now adding the two equations , C(s) + CO2(g) + 2Cl2(g) 2 COCl2(g) K = 46.8 * 10 ^ 8 = 4.68 * 10 ^ 9 b) Kp =P2 COCl2 / P2Cl2PCO2Related Questions
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