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the following equilibrium constants were determined at 1123K: C (s)+ CO 2 (g) 2C

ID: 678773 • Letter: T

Question

the following equilibrium constants were determined at 1123K: C (s)+ CO2(g) 2CO(g)         K'p= 1.3 * 1014 CO (g)+ Cl2(g) COCl2(g)      K''p=6.00*10-3 a) Calculate the equilibrium constant at 1123 K for thereaction: C(s)+ CO2(g)+ 2 Cl2(g) 2COCl2(g) b) Write the equilibrium constant expression, Kp ?Write the pressure in the following formate: (PCO) the following equilibrium constants were determined at 1123K: C (s)+ CO2(g) 2CO(g)         K'p= 1.3 * 1014 CO (g)+ Cl2(g) COCl2(g)      K''p=6.00*10-3 a) Calculate the equilibrium constant at 1123 K for thereaction: C(s)+ CO2(g)+ 2 Cl2(g) 2COCl2(g) b) Write the equilibrium constant expression, Kp ?Write the pressure in the following formate: (PCO) a) Calculate the equilibrium constant at 1123 K for thereaction: C(s)+ CO2(g)+ 2 Cl2(g) 2COCl2(g) b) Write the equilibrium constant expression, Kp ?Write the pressure in the following formate: (PCO)

Explanation / Answer

             C (s)+ CO2(g) 2CO(g)         K'p= 1.3 * 1014 Multipling with 2 to the equation 2 ,               2 CO (g)+ 2Cl2(g) 2COCl2(g)       K''p= 36 * 10 ^ -6 Now adding the two equations ,            C(s) +  CO2(g) + 2Cl2(g) 2 COCl2(g)      K =    46.8 *   10 ^ 8                                                                                          = 4.68 * 10 ^ 9 b) Kp =P2 COCl2 / P2Cl2PCO2 Multipling with 2 to the equation 2 ,               2 CO (g)+ 2Cl2(g) 2COCl2(g)       K''p= 36 * 10 ^ -6 Now adding the two equations ,            C(s) +  CO2(g) + 2Cl2(g) 2 COCl2(g)      K =    46.8 *   10 ^ 8                                                                                          = 4.68 * 10 ^ 9 b) Kp =P2 COCl2 / P2Cl2PCO2