Given the same reactant concentration, thereaction CO(g) + Cl2(g) COCl2(g) at 22

Question

Given the same reactant concentration, thereaction
CO(g) + Cl2(g) COCl2(g)
at 225 degree C is 74.5 times as fast as the same reaction at 145degree C. Calculate the activation energy for this reaction. Assumethat the frequency factor is constant. (Answer in kJ/mol) Given the same reactant concentration, thereaction
CO(g) + Cl2(g) COCl2(g)
at 225 degree C is 74.5 times as fast as the same reaction at 145degree C. Calculate the activation energy for this reaction. Assumethat the frequency factor is constant. (Answer in kJ/mol)

Explanation / Answer

Equation: ln(k1/k2) = (Ea/R)(1/T2 - 1/T1) Let K at 145 C be 1, so K at 225 (74.5 times faster) is 74.5 Ea= unknown R = 8.3145 T2= 145 + 273 = 418 K T1 = 225 + 273 = 498 K K1 = 74.5 k2 = 1 ln(74.5/1) = (Ea/8.3145)(1/418 - 1/498) Ea = 93263 J/mol or 93.3KJ/mol

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