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Any help. Cant figure out this one. Thanks for yourhelp! For the decomposition o

ID: 678311 • Letter: A

Question

Any help. Cant figure out this one. Thanks for yourhelp!
For the decomposition of gaseous dinitrogen pentoxide (shownbelow), the rate constant is k = 2.8 multiplied by 10-3 s-1 at60°C. The initial concentration of N2O5 is 1.11 mol/L.
2 N2O5(g) 4 NO2(g) + O2(g)
(a) What is [N2O5] after 7.00 min? ________ mol/L
(b) What fraction of the N2O5 has decomposed after 7.00min?
Any help. Cant figure out this one. Thanks for yourhelp!
For the decomposition of gaseous dinitrogen pentoxide (shownbelow), the rate constant is k = 2.8 multiplied by 10-3 s-1 at60°C. The initial concentration of N2O5 is 1.11 mol/L.
2 N2O5(g) 4 NO2(g) + O2(g)
(a) What is [N2O5] after 7.00 min? ________ mol/L
(b) What fraction of the N2O5 has decomposed after 7.00min?

Explanation / Answer

Equation: ln[A] = -kt + ln[A] a) 7 min x 60 s/min = 420 seconds ln[N2O5] = (-2.8e-3 s-1)(420) + ln(1.11) [N2O5] = .3424 mol/L b. Final amount: .3424 and initial was 1.11 Amount decomposed: 1.11 - .3424 = .7676 Fraction decomposed: .7676 / 1.11 = .692

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