Write the chemical equation for the reactionthat occurs. Express your answer as
ID: 678118 • Letter: W
Question
Write the chemical equation for the reactionthat occurs. Express your answer as a balancedchemical equation. Identify all of the phases in your answer.Part B Which is the limiting reactant in thereaction? Express your answer as a chemicalformula.
Part C
Part D
Part E
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please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
please make sure the answer is correctthank you need a life saver!!
Explanation / Answer
2HNO3 + Mg(OH)2 -> Mg(NO3)2 + 2H2O To find the limiting reactant first Obtain the number of moles ofeach substance 0.2 M x 0.026 L = 0.0052 moles of HNO3 Rmm of MgOH2 = 58.1398 g/mol Therefore 5.51g/ 58.1398 =0.0948 moles of MgOH2 the ratio of MgOH2 : HNO3 is 1:2 there the amount of HNO3 required is 0.0948 moles x 2 moles HNO3/1 mole MgOH2 = 0.190 moles therefore HNO3 is the limiting reactant. after the reaction only 0.0026 moles of MgOH2 is used therefore0.948-0.0026 = 0.0922 moles remain All moles of HNO3 are used up ANS= 0 since MgNO32 is in the same ratio as MgOH2 only 0.0026 moles are present after the reaction
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