Vapor pressure of water at 25.0 degree C is 23.8 torr.Determine the mass of gloc

Question

Vapor pressure of water at 25.0 degree C is 23.8 torr.Determine the mass of glocose (molar mass 180g/mol) needed to addto 500.0 g of water to change the vapor pressure to 23.4 torr.(ignore significant figures for this problem). A. 85 g B. 6.4 kg C. 183 g D. 177 g E. 8.5 g Vapor pressure of water at 25.0 degree C is 23.8 torr.Determine the mass of glocose (molar mass 180g/mol) needed to addto 500.0 g of water to change the vapor pressure to 23.4 torr.(ignore significant figures for this problem). A. 85 g B. 6.4 kg C. 183 g D. 177 g E. 8.5 g

Explanation / Answer

Moles of water = 500 / 18.02 = 27.7 23.4 = 23.8 x (mole fraction of water) mole fraction of water = 23.4/23.8 = .983 .983 = moles of water / (moles of water + moles of glucose) .983 = 27.7 moles / (27.7 moles + X) x = .474 = moles of glucose Molar mass = 180 g/mol .474 moles x (180 g/mol) = 85.38 g Answer A

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