state ice water steam specific heat j/g. degree C 2.06 4.18 2.03 molar heat of f

Question

state ice water steam specific heat j/g. degree C 2.06 4.18 2.03 molar heat of fusion for water kj/mol 6.02 molar heat of vaporization for water kj/mol 40.6
use the information given above, calculate the energy involvedin the conversion of 291 g of steam at 373k to ice at 243k. be sureto use the correct sign. state ice water steam specific heat j/g. degree C 2.06 4.18 2.03 molar heat of fusion for water kj/mol 6.02 molar heat of vaporization for water kj/mol 40.6 molar heat of fusion for water kj/mol 6.02 molar heat of vaporization for water kj/mol 40.6
use the information given above, calculate the energy involvedin the conversion of 291 g of steam at 373k to ice at 243k. be sureto use the correct sign. state ice water steam specific heat j/g. degree C 2.06 4.18 2.03

Explanation / Answer

To solve the problem you have to find the heat from phase to phaseand temperature to temperature within a phase. The conversions involved are: 1.373 K steam to 373 K water (note 373 K = 100 °C ) 2.373 K water to 273 K water ( note 273 K = 0 °C) 3.273 K water to 273 K ice 4.273K water to 243 k ice For step 1 you divide the weight in grams by the molecular weightof water (finding moles). You then mulitply by the molar heat ofvaporization for water. 1. ((291 g)/(18.01 g/mol))(40.6 kj/mol) = 656 KJ For step 2 you multiply the weight in grams by the specific heat ofwater and by the change in temperature in degrees celcius. 2. (291 g)(4.184 j/g °C)(-100 °C) = -121754.4 J

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.