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Question

Given the rate equation...
RATE = ([ Na2S2O3]/time) = k [I-]a [BrO3-]b [HCl]c
1A) You mix together in the proper manner the following:

* 10.0 mL of .0100 M Potassium Iodide
* 10.0 mL of .00100 M Sodium thiosulfate
* 10.0 mL of water
* 10.0 mL of .0400 M Potassium Bromate
* 10.0 mL of .100 M HCl

The time to turn blue is... 48 sec

1B) You also mix together in the proper manner the following:

* 10.0 mL of .0100 M Potassium Iodide
* 10.0 mL of .00100 M Sodium thiosulfate
* 20.0 mL of .0400 M Potassium Bromate
* 10.0 mL of .100 M HCl

The time to turn blue is... 11 sec
Calculate:
The Experimental value of exponent b..._______________ (a)

2) If the exponents a, b, and c have the values:
a = 2; b = 2; c = 0
CALCULATE:
Rate constant k for data in 1A...______________ (b)

3) You mix together in the proper manner the following VOLUMES:

* 0.0100 M Potassium iodide...14.9 mL
* 0.0010 M Sodium thiosulfate...8.9 mL
* Distilled water...21.6 mL
* 0.0400 M Potassium Bromate...8.7 mL
* 0.100 M Hydrochloric acid...13.5 mL

Using the rate constant and rate equation from problem 2),

CALCULATE the time to turn blue...__________________ sec (c)

4) A plot of log Rate vs 1/T gives a best straight line which goesthrough....
1/T = 0.00300, log rate = -4.37
and 1/T = 0.00351, log rate = -6.00.
CALCULATE:
The Slope of the line..._____________ (d)

The Activation Energy (Ea) (Kj/mol)...________________(e)

Thank you for your help! Given the rate equation...
RATE = ([ Na2S2O3]/time) = k [I-]a [BrO3-]b [HCl]c
1A) You mix together in the proper manner the following:

* 10.0 mL of .0100 M Potassium Iodide
* 10.0 mL of .00100 M Sodium thiosulfate
* 10.0 mL of water
* 10.0 mL of .0400 M Potassium Bromate
* 10.0 mL of .100 M HCl

The time to turn blue is... 48 sec

1B) You also mix together in the proper manner the following:

* 10.0 mL of .0100 M Potassium Iodide
* 10.0 mL of .00100 M Sodium thiosulfate
* 20.0 mL of .0400 M Potassium Bromate
* 10.0 mL of .100 M HCl

The time to turn blue is... 11 sec
Calculate:
The Experimental value of exponent b..._______________ (a)

2) If the exponents a, b, and c have the values:
a = 2; b = 2; c = 0
CALCULATE:
Rate constant k for data in 1A...______________ (b)

3) You mix together in the proper manner the following VOLUMES:

* 0.0100 M Potassium iodide...14.9 mL
* 0.0010 M Sodium thiosulfate...8.9 mL
* Distilled water...21.6 mL
* 0.0400 M Potassium Bromate...8.7 mL
* 0.100 M Hydrochloric acid...13.5 mL

Using the rate constant and rate equation from problem 2),

CALCULATE the time to turn blue...__________________ sec (c)

4) A plot of log Rate vs 1/T gives a best straight line which goesthrough....
1/T = 0.00300, log rate = -4.37
and 1/T = 0.00351, log rate = -6.00.
CALCULATE:
The Slope of the line..._____________ (d)

The Activation Energy (Ea) (Kj/mol)...________________(e)

Thank you for your help!

Explanation / Answer

Not good with chemistry myself, but I can tell you that the info you have should be enough to determine the order of the rxn. It looks like in 1B you doubled the amount of potassium bromate, and it cut the rxn time down by 1/4th or 1/5th. Once you figure out the order of the rxn rate, you can plug in the values into the equation you're given, and it will all fall into place.

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