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Okay i\'m having difficulty setting up these kinds ofproblems...i\'m not really

ID: 676684 • Letter: O

Question

Okay i'm having difficulty setting up these kinds ofproblems...i'm not really sure where to begin and so on...Here'sthe question: The concentration (M) of HCL in the solution prepared bydissolving 5.5 g of HCL in 200 g of water is _____________ M. The density of the solution is 0.79g/ml. Someone please help ASAP!!! Okay i'm having difficulty setting up these kinds ofproblems...i'm not really sure where to begin and so on...Here'sthe question: The concentration (M) of HCL in the solution prepared bydissolving 5.5 g of HCL in 200 g of water is _____________ M. The density of the solution is 0.79g/ml. Someone please help ASAP!!!

Explanation / Answer

This is a units-conversion problem The question asks for Molarity which is moles/L, so convert all thegiven values toward these 5.5 g HCl * (1 mol/36.46 g) = .15 moles   (molarcomponent done) The liquid (liters) is given as a mass instead of a volumetherefore we need a density (.79 g/ml) to convert it. 200g of water / (.79g/mL) = 253 mL * (1 L/ 1000 mL) =.253 liters (liters component done) finally, .15 moles/ .253 liters = .59 M In these types of problems it is best first to identify what youneed and what you have the try to form a link between the two.

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