Iodine solvent was added to a test tube. It is solid and nonpolar. When water wa

Question

Iodine solvent was added to a test tube. It is solid and nonpolar. When water was added, it turned from clear to ayellowish-brown. The mixture was immiscible. Hexane was added andthe mixture separated into two layers, one yellow-broen and oneclear. When it was shaken the clear hexane turned purple. Thehexane dissloved the solid iodine but the solutions were stillimmiscible and in teo layers. the polar hexane dissolved thenon-polar solid, yet still immiscible with water. **what do you think is occuring at the atomic/molecular level?write a chemical equation for the process. Why did this phenomenonoccur? Iodine solvent was added to a test tube. It is solid and nonpolar. When water was added, it turned from clear to ayellowish-brown. The mixture was immiscible. Hexane was added andthe mixture separated into two layers, one yellow-broen and oneclear. When it was shaken the clear hexane turned purple. Thehexane dissloved the solid iodine but the solutions were stillimmiscible and in teo layers. the polar hexane dissolved thenon-polar solid, yet still immiscible with water. **what do you think is occuring at the atomic/molecular level?write a chemical equation for the process. Why did this phenomenonoccur?

Explanation / Answer

Iodine is non polar Water is polar Hexene is non polar As a rule of thumb (like dissolves like) , iodinecan dissolved in Hexane (solvent) but do not soluble in water. That means non polar molecules of Iodine do not interactwith polar water molecules but can interact withnon polar      Hexane molecules. Similarly , polar water molecules do not interact with nonpolar water molecules so that the two solvents do not miscible(still immiscible and in two layers)  .

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.