considering the following I. pure water II. solution of C12H22O11 (m = 0.01) in

Question

considering the following I. pure water
II. solution of C12H22O11 (m = 0.01) in water
III. solution of NaCl (m = 0.01) in water
IV. solution of CaCl2 (m = 0.01) in water

(a) Choose the one with the highest freezing point.1
pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(b) Choose the one with the lowest freezing point.2 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(c) Choose the one with the highest boiling point.3 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(d) Choose the one with the lowest boiling point.4 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(e) Choose the one with the highest osmotic pressure.5 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution

considering the following I. pure water
II. solution of C12H22O11 (m = 0.01) in water
III. solution of NaCl (m = 0.01) in water
IV. solution of CaCl2 (m = 0.01) in water

(a) Choose the one with the highest freezing point.1
pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(b) Choose the one with the lowest freezing point.2 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(c) Choose the one with the highest boiling point.3 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(d) Choose the one with the lowest boiling point.4 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution


(e) Choose the one with the highest osmotic pressure.5 pure water
C12H22O11 solution
NaCl solution
CaCl2 solution

Explanation / Answer

considering the following

I. pure water
II. solution of C12H22O11 (m = 0.01) in water (will not dissociate so effective molality will be 0.01 as van't hoff factor= 1)
III. solution of NaCl (m = 0.01) in water ( will dissociate into two ions so effective molality will be 0.02 as van't hoff factor= 2)
IV. solution of CaCl2 (m = 0.01) in water (will dissociate into three ion so effective molality will be 0.03 as van't hoff factor= 3)

(a) Choose the one with the highest freezing point.

answer: The depression in freezing point is directly proportional to molality. so more the number of ions more the deperssion in freezing point. So highest freezing point will be of pure water with no solute. As solute decreases the freezing point.
pure water

(b) Choose the one with the lowest freezing point.2

answer: The depression in freezing point is directly proportional to molality. so more the number of ions more the deperssion in freezing point. So lowest freezing point will be of CaCl2 solution

(c) Choose the one with the highest boiling point.3

answer: The elevation boiling point is directly proportional to molality. so more the number of ions more the elevation inboiling point. So highest boiling point will be of solution with highest molality. As solute increases the boiling point

CaCl2 solution

(d) Choose the one with the lowest boiling point.

Answer: the elevation in boiling point is directly proportional to molality. so more the number of ions more the elevation in boiling point. So lowest boiling point will be of pure water As solute increases the boiling point

pure water

(e) Choose the one with the highest osmotic pressure.

Again the osmotic pressure depends upon the number of moles of solute so more the number of moles of solute higher the osmotic pressure : answer is CaCl2

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