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In lab you determined the average masses of popcorn kernels andmarbles. One stud

ID: 676207 • Letter: I

Question

In lab you determined the average masses of popcorn kernels andmarbles. One student got the following results. Your values shouldhave been similar.

Use this student's results to answer the followingquestions.

a. What is the mass of one popcorn kernel?

1 g

b. What is the mass of 2.11 dozen popcorn kernels?

2 g

c. How many popcorn kernels are in a sample that has a mass of49.833 g?

3 kernels

d. What is the mass of one marble?

4 g

e. What is the mass of 2.11 dozen marbles?

5 g

f. What is the relative mass of a single popcorn kernel to asingle marble?

6 (relative mass, so no units!)

Using Avogadro's number, 6.022x1023 things/mole,please answer the following questions. Use e notation for largeanswers (4.9x1016 = 4.9e16).

g. What is the mass of one mole of popcorn kernels?

7 g

h. What is the mass of one mole of marbles?

8 g

i. What is the relative mass of one mole of popcorn kernels toone mole of marbles?

9 (relative mass, so no units!)

j. The relative mass of a single popcornkernel to a single marble is 10---Select---cannot tellequal togreater thanless than the relative mass of a mole of popcorn kernels to a moleof marbles.

Note that the mass of the earth is about 6e27 g and the mass ofthe moon is about 7e25 g.

In lab you determined the volume of 12 marbles and the mass of18.0 mL of water. Use the following data, which should closelyapproximate your results, to answer the questions below.

a. What are the densities determined from the above?

b. The number of moles of water present in 18 g of water is

c. Use e notation (2.2x1021 = 2.2e21) for the numberof water molecules in 18 g of water.

d. What is the mass of a single molecule of water?

e. How many water molecules would have the mass of onemarble?

f. Neglect empty space between molecules and calculate theaverage volume of a water molecule.

g. What is the average volume of a marble?

h. How many water molecules could fit in the same volume as onemarble?

Note that the population of earth is about 6e9 people and thereare about 4e11 stars in the Milky Way galaxy!

3600 seconds = 1 hour 24 hours = 1 day 365 days = 1 year

Explanation / Answer


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