what is the solution in the below formula of the element beingreduced and oxidis

Question

what is the solution in the below formula of the element beingreduced and oxidised witht the answers and labels of thereoxidation state? 1) 2Na + FeCl2 = 2NaCl + Fe 2) 2C2H2 + 5O2 = 4CO2+2H2O 3) 2PbS + 3O2 = 2SO2 +2PbO 4) 2H2 + O2 = 2H2O 5) Cu +HNO3 = CuNO3 + H2 6) AgNO3 +Cu = CuNO3 + Ag what is the solution in the below formula of the element beingreduced and oxidised witht the answers and labels of thereoxidation state? 1) 2Na + FeCl2 = 2NaCl + Fe 2) 2C2H2 + 5O2 = 4CO2+2H2O 3) 2PbS + 3O2 = 2SO2 +2PbO 4) 2H2 + O2 = 2H2O 5) Cu +HNO3 = CuNO3 + H2 6) AgNO3 +Cu = CuNO3 + Ag

Explanation / Answer

I don't quite understand the question, but reduction is merely thegaining of electrons. So for the 1st equation Fe goes from Fe2+ toFe by being reduced (i.e. gaining two electrons). Hope thishelps.

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