This is the file with your answer, do not ren Write your code in it, and save it

Question

This is the file with your answer, do not ren Write your code in it, and save it before sub def is valid_socket_address (socket address): a=socket-address. split('·') if len(a) 5: return False for y in range(o,len(a)-1) for x in a: if not x.isdigit(): return False t int(x) if ice or ix255: if y=4 if ice or 1 65535 return False return False return True # This tests your code with the exaples given in the # and is provided only for your convenience. tr for socket_address in ["127.12.23.43:5880" "127.A:-12"]: print ts valid_socket_address(socket_address) Pyt Python split, replace

Explanation / Answer

def is_valid_socket(socket_address):
a = socket_address.split(':')
b = a[0].split('.')
if len(a)!= 2:
return False
if len(b)!=4 :
return False
for i in range(4):
if not b[i].isdigit():
return False
j = int(b[i])
if j < 0 or j > 255:
return False
if not a[1].isdigit():
return False
j = int(a[1])
if j < 0 or j > 7685 :
return False
return True
for socket_address in ['17.1.2.78:7256', '127.A:-5']:
print is_valid_socket(socket_address)
  

you are splitting the address only with " . " but address contain " : " also

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.