Write an application that inputs an integer containing only 0s and 1s (i.e., bin

Question

Write an application that inputs an integer containing only 0s and 1s (i.e., binary integer) and prints its decimal equivalent. [Hint: Use the remainder and division operators to pick off the binary number's digits one at a time, from right to left. In decimal number system, the rightmost digit has a positional value of 1 and the next digit to the left a positional vlaue of 10, the 100, then 1000, and so on. The decimal number 234 can be interpreted as 4 * 1 + 3 * 10 + 2 * 100. In the binary number system, the rightmost digit has a positional value of 1, the next digit to the left a positional value of 2, then 4, then 8, and so on. The decimal equivalent of binary 1101 is 1 * 1 + 0 * 2 + 1 * 4 + 1 * 8, or 1 + 0 + 4 + 8, or 13.]

Explanation / Answer

#include<iostream.h>
#include<conio.h>
#include<math.h>
void main()
{
   int bi,sum=0,i=0,a;

   cout<<"Enter no";
   cin>>bi;

   while(bi>0)
   {
       a=bi%10;
       sum=sum+(a*pow(2,i));
       bi=bi/10;
       i++;
   }

   cout<<sum;
   getch();

}

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