by C++please? . each version should be separated Thank you Version 1 (all intera
ID: 670121 • Letter: B
Question
by C++please? . each version should be separated Thank you
Version 1 (all interactive). Write a program that reads in the average
monthly rainfall for a city for each month of the year and then reads in
the actual monthly rainfall for each of the previous 12 months. The
program then prints out a nicely formatted table showing the rainfall for
each of the previous 12 months as well as how much above or below
average the rainfall was for each month. The average monthly rainfall is
given for the months January, February, and so forth, in order. To obtain
the actual rainfall for the previous 12 months, the program first asks what
the current month is and then asks for the rainfall figures for the previous
12 months. The output should correctly label the months.
There are a variety of ways to deal with the month names. One
straightforward method is to code the months as integers and then do
a conversion before doing the output. A large switch statement is
acceptable in an output function. The month input can be handled in
any manner you wish, as long as it is relatively easy and pleasant for
the user.
After you have completed this program, produce an enhanced version
that also outputs a graph showing the average rainfall and the actual
rainfall for each of the previous 12 months. The graph should be similar
to the one shown in Display 7.8, except that there should be two bar
graphs for each month and they should be labeled as the average rainfall
and the rainfall for the most recent month. Your program should ask the
user whether she or he wants to see the table or the bar graph and then
should display whichever format is requested. Include a loop that allows
the user to see either format as often as the user wishes until the user
requests that the program end.
Version 2 (combines interactive and file output). For a more elaborate
version, also allow the user to request that the table and graph be output
to a file. The file name is entered by the user. This program does
everything that the Version 1 program does, but has this added feature. To
read a file name, you must use material presented in the optional section
of Chapter 5 entitled “File Names as Input.”
Version 3 (all I/O with files). This version is like Version 1 except that
input is taken from a file and the output is sent to a file. Since there is
no user to interact with, there is no loop to allow repeating the
display; both the table and the graph are output to the same file. If this
is a class assignment, ask your instructor for instructions on what file
names to use.
Explanation / Answer
// Display all the recorded data
void displayAll(struct monthly_rainfall *head){
while(head == NULL) return;
cout << head->month << " " << head->year << " " << head->rainfall_inch << endl;
displayAll(head->next);
}
// Finds and changes the rainfall data for a given month and year. The return value should be 0 if it was able to find the entry and -1 if no entry could be found.
int changeEntry(struct monthly_rainfall *head, int year, int month, float rainfall){
if(head == NULL) return -1;
if(head->month == month && head->year == year) head->rainfall_inch = rainfall;
return 0;
}
// Find the entry with highest monthly rainfall in the logged data and return a pointer to this structure
struct monthly_rainfall *findHighestRainfall(struct monthly_rainfall *head){
if(head->next == NULL) return head;
prev = findHighestRainfall(head->next);
if(head->rainfall_inch > prev->rainfall_inch) return head;
return prev;
}
// Find the entry with lowest monthly rainfall in the logged data and return a pointer to this structure
struct monthly_rainfall *findLowestRainfall(struct monthly_rainfall *head){
if(head->next == NULL) return head;
prev = findLowestRainfall(head->next);
if(head->rainfall_inch > prev->rainfall_inch) return head;
return prev;
}
// Calculate the monthly average over all the logged data
float calcAverageRainfall(struct monthly_rainfall *head){
int sum =0;
while( head != NULL) sum += head->rainfall_inch, head = head->next;
return sum*1.0/12;
}
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