When a method in a subclass has the same signature as a method in a superclass (

Question

When a method in a subclass has the same signature as a method in a superclass (same name, same parameters and same return type) we say the that method in the subclass______________ the method in the superclass.

Here is the code for class Atrium

Here is the code for class Lobby, but missing the body for the constructor.

Write the code for the constructor.

An ArrayList is declared by the following code:

Assume that names has been initialized and values have been added to the ArrayList. Write the code that will, for each element in the ArrayList, print the element followed by the string length of the element on a line.

For example, if the ArrayList had the names "Abel", "Charlie", "Baker" in it, then the output might look like this:

Explanation / Answer

When a method in a subclass has the same signature as a method in a superclass (same name, same parameters and same return type) we say the that method in the subclass___Override__ the method in the superclass.

public Lobby(int windows, String label, in doors){
super(int windows, String label);
}

import java.util.ArrayList;

public class Size {

public static void main(String[] args) {

ArrayList arrayList = new ArrayList();
int a;   

arrayList.add("Abel");
arrayList.add("Charlie");
arrayList.add("Baker");


int totalElements = arrayList.size();

System.out.println("ArrayList contains...");
//loop through it
for (String n : arrayList) {
a=n.length();
System.out.println(n+" "+a);

}

}

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