CAN YOU PLZ HELP ME CODE IN JAVA USING ECLIPSE I WILL RATE :) DONT USE THE JOPTI
ID: 670022 • Letter: C
Question
CAN YOU PLZ HELP ME CODE IN JAVA USING ECLIPSE I WILL RATE :)
DONT USE THE JOPTION. FORM THANK YOU!
Days in a Month
Write a class named MonthDays. The class’s constructor should accept two arguments:
*An integer for the month (1= January,2 February,ect,).
*An integer for the year
The class should have a method named getNumberOfDays that returns the number of days in the specified month. The method should use the following criteria to identify leap years:
1. Determine whether the year is divisible by 100. If it is, then it is a leap year if and if only it is divisible by 400. For example, 2000 is a leap year but 2100 is not.
2. If the year is not divisible by 100, then it is a leap year if and if only it is divisible by 4. For example, 2008 is a leap year but 2009 is not.
Demonstrate the class in a program that asks the user to enter the month (letting the user enter an integer in the range of 1 through 12) and the year . The program should then display the number of days in that month. Here is a sample run of the program.
Print out:
Enter a month (1-12): 2 [Enter]
Enter a year: 2008 [Enter]
29 days
Explanation / Answer
import java.util.Scanner;
class MonthDays
{
int month;
int year;
public MonthDays(int m, int y)
{
month = m;
year = y;
}
public int getNumberOfDays()
{
int mnt[] = {31,28,31,30,31,30,31,31,30,31,30,31};
if(month==2)
{
if((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0)))
{
return 29;
}
else return 28;
}
else return mnt[month-1];
}
}
public class Test
{
public static void main(String args[])
{
int m,y,days;
Scanner scan = new Scanner(System.in);
System.out.println("enter the month");
m=scan.nextInt();
System.out.println("enter the year");
y=scan.nextInt();
MonthDays a = new MonthDays(m,y);
days=a.getNumberOfDays();
System.out.println(days);
}
}
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.