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Suppose you are using packet switching. What is the maximum number of users that

ID: 667859 • Letter: S

Question

Suppose you are using packet switching. What is the maximum number of users that can be supported if the required blocking probability is strictly less than .05. Users share a 2Gbps link and each user requires 400 Mbps when transmitting, but only transmits 30% of the time.

So I understand:

P(transmitting) = .3

P(not transmitting) = .7

I also know that P(n users simultaneously transmitting) = (total users "choose" n) (.3^n) * (.7^(total users - n))

But I have no idea how to proceed with the problem. Thank you for your help in advance.

Explanation / Answer

Solution : According to the question -

It is given that the blocking probability is strictly less than 0.05.

Users share 2Gbps and each user require 400Mbps.

Transmit 30% only.

As we known - [ 1 = 0.3 + 0.7 ]

So, Firstly convert 400Mbps into Gbps. i.e.; 1000Mb = 1Gb

400 Mb = xGb

We get, xGb = 400/1000 = 0.4Gb

Then we can calculate the maximum number of users = 20Gbps/0.4Gbps

= 5Gbps

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