Question 3: Suppose that you have the following variable declarations: int x = 2

Question

Question 3: Suppose that you have the following variable declarations:

                int x = 20;

                int y = 35;

                int z = 40;

    Determine whether the following expressions are true or false.

                a. !(x < 100)

                b. x <= 5 || y > 15

                c. (x != 5) && (y == z)

                d. x <= z && (x + y >= z)

Question 5: What is the output from the following C++ code fragment?

                int x = 100;

                if (x <= 0)

{

                                cout << “x is a non-positive value” << endl;

}

Question 6: What is the output from the following C++ code fragment?

                int x = 0;

                if (x < 0)

{

                                cout << “x is a negative value” << endl;

}

else

{

                cout << “x is a non-negative value” << endl;

}

Explanation / Answer

given x =20, y=35, z=40

a) !(x<100)
firstly x<100 ==>20<100 ==>true but !True ===>False
b) x<=5 || y>15
20<=5 False
35>15 ==> true
so OR operator true
c) (x!=5)&&(y==z)
(20!=5)&&(35==40)
False && False
False

d) x <= z && (x + y >= z)
20 <=40 && (20 + 35 >=40)
true && true
True

----------------------------------------------------------
question 5:

int x = 100;
if (x <= 0)
{
cout << “x is a non-positive value” << endl;
}

since x is positive number and greater than zero...so it doesn't pass inside is loop...So i doesnt print anything

------------------------------------------------------
int x = 0;
if (x < 0)
{
cout << “x is a negative value” << endl;
}
else
{
cout << “x is a non-negative value” << endl;
}

since x is given zero....first it check with if condition x<0....but xis not less than zero..it is zero
So, it goes through else condition...so it print " x is a non-negative value"

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