Long-Distance Calls A long-distance carrier charges the following rates for tele

Question

Long-Distance Calls   A long-distance carrier charges the following rates for telephone calls:   Starting Time of Call Rate per Minute   00:00–06:59 0.05 07:00–19:00 0.45 19:01–23:59 0.20 Write a program that asks for the starting time and the number of minutes of the call, and displays the charges. The program should ask for the time to be entered as a floating- point number in the form HH.MM. For example, 07:00 hours will be entered as 07.00, and 16:28 hours will be entered as 16.28.   Input Validation: The program should not accept times that are greater than 23:59. Also, no number whose last two digits are greater than 59 should be accepted. Hint: Assuming num is a floating-point variable, the following expression will give you its fractional part:     num static_cast<int>(num)
Copyright | Addison-Wesley | Starting Out with C++ | Edition 8 | lynn.crum@hotmail.com | Printed from www.chegg.com

Explanation / Answer

#include<iostream.h>
int main()
{
   float start_time,end_time;
   while(1)
   {
   cout<<"enter starting time ";
   cin>>start_time;
   int intpart = (int)start_time;
    double decpart = start_time - intpart;
   cout<<"enter end time ";
   cin>>end_time;
   int intpart1 = (int)end_time;
    double decpart1 = end_time - intpart1;
   if ((start_time > 23.59) || (end_time > 23.59) || (decpart1 > 0.6) || (decpart > 0.6))
   {
   cout<<"time is not valid.re-enter ";
   continue;
   }
   else
   {
       break;
   }
   }
   float balance,charge,mid;
   balance = end_time - start_time;
   if (balance < 6.59)
   charge = 0.05 * balance;
   else if (balance < 19.01)
   {
   mid=balance - 6.59;
   charge = 0.3295 + (mid*0.10);
   }
   else
   {
   mid = balance - 19;
   charge = 1.5295 + (mid*0.20);
   }
   cout<<"charge is "<<charge;
  
}
   

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