Write a method named sequenceSum that prints terms of the following mathematical

Question

Write a method named sequenceSum that prints terms of the following mathematical sequence:

Your method should accept a real number as a parameter representing a limit, and should add and print terms of the sequence until the sum of terms meets or exceeds that limit. For example, if your method is passed 2.0, print terms until the sum of those terms is at >= 2.0. You should round your answer to 3 digits past the decimal point.

The following is the output from the call sequenceSum(2.0);

1 + 1/2 + 1/3 + 1/4 = 2.083

(Despite the fact that the terms keep getting smaller, the sequence can actually produce an arbitrarily large sum if enough terms are added.) If your method is passed a value less than 1.0, no output should be produced. You must match the output format shown exactly; note the spaces and pluses separating neighboring terms. Other sample calls:

call: sequenceSum(0.0); sequenceSum(1.0); sequenceSum(1.5); output: 1 = 1.000 1 + 1/2 = 1.500 call: sequenceSum(2.7); output: 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 = 2.718

Explanation / Answer

class Sequence
{
public static void main(String...s)
{
int n,i;
float sum=0;

n=Integer.parseInt(s[0]);
  
for(i=1;i<=n;i++)
{
sum=sum+(float)1/i;
}

System.out.println(" Sum="+sum);
}
}

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