A firm is assigned the network part 128.171. It selects an 8-bit subnet part. a)

ID: 656336 • Letter: A

Question

A firm is assigned the network part 128.171. It selects an 8-bit subnet part.

a) Draw the bits for the four octets of the IP address of the first host on the first subnet. (Hint: Use Windows Calculator.)

b) Convert this answer into dotted decimal notation.

c) Draw the bits for the second host on the third subnet. (In binary, 2 is 10, while 3 is 11.)

d) Convert this into dotted decimal notation.

e) Draw the bits for the last host on the third subnet.

f) Convert this answer into dotted decimal notation.

1)
given 128.171
that means first address would be 128.171.1.1 -->now we have convert integer to decimal

128->10000000 -->2^7=128
171->10101011--->128+0+32+0+16+0+2+1=171
1->00000001

finally 10000000.10101011.00000001.00000001

2)
convert to dotted notation...already i explained in above answer
128.171.1.1

3)
as you want second host on the third subnet
so
third subnet means 11 and second host means 10 --->given in question already

so 10000000.10101011.00000011.00000010

4)
converting decimal notation
10000000.10101011.00000011.00000010
127 . 171 . 3 . 2

===>127.171.3.2

5)
bits for the last host on the third subnet. ..so last host would be 254--->it would be 11111110

6)so dotted notation will be 10000000.10101011.00000011.11111110(127.171.3.254)

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