The network has background traffic of Tb = 10 units on each edge. The connection
ID: 651581 • Letter: T
Question
The network has background traffic of Tb = 10 units on each edge. The connection from S to D generates traffic of 20 units on each edge on the path from S to D. Total traffic on an edge is the sum of traffic from S to D, if any, and the background traffic.
What is the initial quickest path selected by the node S to send data to node D? After the sender S starts sending data to D and the next cycle of network delay information update is over, what is the quickest path selected by the node S to send data to node D? Does this path again change after the next cycle of network delay?
Explanation / Answer
the initial transmission starts from s to D via node A. since the total delay from S to D is 120 units. After the first packet is sent then the path will remain same in the above network because the shortest path from S to D is S-A-D and other path is not like this path having only 2 edges between S and D.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.