How do I fix the infinite loop if the user inputs an invalid input? #include \"s

Question

How do I fix the infinite loop if the user inputs an invalid input?

#include "stdafx.h"
#include
#include
#include
#include
using namespace std;

struct menuItemType
{
   string menuItem;
   double menuPrice;
};

void getData(menuItemType menuList[8]);
void showMenu(menuItemType menuList[8]);
void printCheck(menuItemType menuList[8]);

int main()
{
   menuItemType menuList[8];

   getData(menuList);
   showMenu(menuList);
   printCheck(menuList);
   _getch();
   return 0;
}

void getData(menuItemType menuList[8])
{

   menuList[0].menuItem = "Plain Egg";
   menuList[0].menuPrice = 1.45;
   menuList[1].menuItem = "Bacon and Egg";
   menuList[1].menuPrice = 2.45;
   menuList[2].menuItem = "Muffin";
   menuList[2].menuPrice = 0.99;
   menuList[3].menuItem = "French Toast";
   menuList[3].menuPrice = 1.99;
   menuList[4].menuItem = "Fruit Basket";
   menuList[4].menuPrice = 2.49;
   menuList[5].menuItem = "Cereal";
   menuList[5].menuPrice = 0.69;
   menuList[6].menuItem = "Coffee";
   menuList[6].menuPrice = 0.50;
   menuList[7].menuItem = "Tea";
   menuList[7].menuPrice = 0.75;

}

void showMenu(menuItemType menuList[8])
{
   cout << "Enter the number of your selections until you are finished, then enter -1. " << endl;
   cout << "1 - Plain Egg" << setw(14) << "$1.45" << endl;
   cout << "2 - Bacon and Egg" << setw(10) << "$2.45" << endl;
   cout << "3 - Muffin" << setw(17) << "$0.99" << endl;
   cout << "4 - French Toast" << setw(11) << "$1.99" << endl;
   cout << "5 - Fruit Basket" << setw(11) << "$2.49" << endl;
   cout << "6 - Cereal" << setw(17) << "$0.69" << endl;
   cout << "7 - Coffee" << setw(17) << "$0.50" << endl;
   cout << "8 - Tea" << setw(21) << "$0.75 " << endl;
}

void printCheck(menuItemType menuList[8])
{
   int selections = 0;

   while (selections != -1)
   {
       cout << " Enter selection: ";
       selections += selections;
       cin >> selections;

       switch (selections)
       {
       case -1:
           break;
       case 1:
           cout << menuList[0].menuItem << setw(14) << "$1.45";
           break;
       case 2:
           cout << menuList[1].menuItem << setw(10) << "$2.45";
           break;
       case 3:
           cout << menuList[2].menuItem << setw(17) << "$0.99";
           break;
       case 4:
           cout << menuList[3].menuItem << setw(11) << "$1.99";
           break;
       case 5:
           cout << menuList[4].menuItem << setw(11) << "$2.49";
           break;
       case 6:
           cout << menuList[5].menuItem << setw(17) << "$0.69";
           break;
       case 7:
           cout << menuList[6].menuItem << setw(17) << "$0.50";
           break;
       case 8:
           cout << menuList[7].menuItem << setw(20) << "$0.75";
           break;
       default:
           cout << "Selections must be between 1 and 8 ";
           break;

          
       }
   }
   cout << " Welcome to Josh's Restaurant" << endl;
   cout << "Tax" << setw(10) << endl;
   cout << "Amount Due" << setw(10) << endl;

  
}

Explanation / Answer

The default case can be used for performing a task when none of the cases is true. No break is needed in the default case.

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