Snouters are small critters that live on both sides of the Ohio River. A populat

Question

Snouters are small critters that live on both sides of the Ohio River. A population on the north side of the Ohio is fixed for an allele that codes for blue feet. The south side of the river is fixed for an allele for pink feet. Seventy blue-footed snouters from the north and 30 pink-footed snouters from the south colonize a newly formed island in the middle of the river. Please calculate the following.

What are the genotype frequencies at the time of colonization? (Just the colonizers before reproduction)



What are the allele frequencies at the time of colonization? (Just the colonizers before reproduction, prior to random mating so they are not in H-W equilibrium)



What are the genotype frequencies of the offspring of the next generation (F1 ), assuming random mating?



What are the allele frequencies of the offspring of the next generation (F1 )?

Heterozygotes have purple feet that are susceptible to snouter purple-foot fungus that sterilizes purple-footed snouters (They cannot reproduce). Assume that the F1 generation are the parents for the next set of questions.

Calculate the allele frequencies of the parents that can breed (F1 with no purple footed individuals). Calculate the genotype and allele frequencies of the offspring in the second generation (F2) assuming random mating (Hint: the allele frequency of the parents are equal to the sum of the homozygote frequencies which are equal to 1, It may help if you assume a population size of the reproducing parents.)






Has evolution occurred? If so what evolutionary mechanism was it? If the purple foot fungus were to continue on this island for several generations, what color feet would most likely become fixed on the island and why?

Explanation / Answer

freq at time of colonization: blue*blue: .7 pink*pink: .3 blue*blue: .49 pink*pink: .09 blue*pink: .42 allele frequencies: blue: .7 pink: .3 frequencies of parents that can breed: .49/(.49+.09) for blue homozygous .09/(.49+.09) for pink homozygous answer is same for both genotype and allele yes evolution has occurred. It is disruptive selection. Blue feet are likely to become fixed on the island

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