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10.3 Year Male Female Year Male Female 1979 70.0 77.4 1992 72.1 78.9 1980 70.0 7

ID: 641177 • Letter: 1

Question

10.3

Year

Male

Female

Year

Male

Female

1979

70.0

77.4

1992

72.1

78.9

1980

70.0

77.5

1993

72.1

78.9

1981

70.4

77.8

1994

72.4

79.0

1982

70.9

78.1

1995

72.5

78.9

1983

71.0

78.1

1996

73.1

79.1

1984

71.2

78.2

1997

73.6

79.4

1985

71.2

78.2

1998

73.8

79.5

1986

71.3

78.3

1999

73.9

79.4

1987

71.5

78.4

2000

74.3

79.7

1988

71.5

78.3

2001

74.4

79.8

1989

71.7

78.5

2002

74.5

79.9

1990

71.8

78.8

2003

74.7

80.0

1991

72.0

78.9

2004

75.2

80.4

Problem 10.3. Generate a MATLAB script to load a data file called

Year

Male

Female

Year

Male

Female

1979

70.0

77.4

1992

72.1

78.9

1980

70.0

77.5

1993

72.1

78.9

1981

70.4

77.8

1994

72.4

79.0

1982

70.9

78.1

1995

72.5

78.9

1983

71.0

78.1

1996

73.1

79.1

1984

71.2

78.2

1997

73.6

79.4

1985

71.2

78.2

1998

73.8

79.5

1986

71.3

78.3

1999

73.9

79.4

1987

71.5

78.4

2000

74.3

79.7

1988

71.5

78.3

2001

74.4

79.8

1989

71.7

78.5

2002

74.5

79.9

1990

71.8

78.8

2003

74.7

80.0

1991

72.0

78.9

2004

75.2

80.4

Explanation / Answer

Hi

Feel free to ask if any queries and kindly rate :) .

I have solved another question of yours just now

It takes a lot of effort.

The code is in the zip file.

The link is this.

http://s000.tinyupload.com/index.php?file_id=73732889916601689639

Anyway, the script is

filename = 'life_expectancy.txt';
delimiterIn = ' ';
headerlinesIn = 1;
A = importdata(filename,delimiterIn,headerlinesIn);
Year = A.data(:,1);
Male = A.data(:,2);
Female = A.data(:,3);

mean_men = mean (Male);
mean_women = mean (Female);
median_men = median (Male);
median_women = median (Female);
std_men = std (Male);
std_women = std (Female);
disp('Life Expectancy of Males and Females , at Birth 1979-2004')
disp('          Mean        Median       Standard Deviation')
disp(['Men       ', num2str(mean_men) , '       ', num2str(median_men) ,'       ', num2str(std_men)]);
disp(['Women    ', num2str(mean_women) , '       ', num2str(median_women) ,'        ', num2str(std_women)]);

And the content of txt file is

Year Male Female
1979 70.0 77.4
1980 70.0 77.5
1981 70.4 77.8
1982 70.9 78.1
1983 71.0 78.1
1984 71.2 78.2
1985 71.2 78.2
1986 71.3 78.3
1987 71.5 78.4
1988 71.5 78.3
1989 71.7 78.5
1990 71.8 78.8
1991 72.0 78.9
1992 72.1 78.9
1993 72.1 78.9
1994 72.4 79.0
1995 72.5 78.9
1996 73.1 79.1
1997 73.6 79.4
1998 73.8 79.5
1999 73.9 79.4
2000 74.3 79.7
2001 74.4 79.8
2002 74.5 79.9
2003 74.7 80.0
2004 75.2 80.4

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