Write a program called anagram.c that asks the user for 2 words and tells the us

Question

Write a program called anagram.c that asks the user for 2 words and tells the user if those 2 words are anagrams. A word is an anagram of another word if the letters in that word can be rearranged to form the other word. For example Mary and army are anagrams.

Name your executable anagram.out

The user will only enter alphabetical characters

The maximum length of each word is 20 characters

The check for an anagram should be case insensitive. For example MARY and

army are still anagrams

Examples

Please enter the first word: MaRy Please enter the second word: arMY MaRy is an anagram of arMY

Please enter the first word: dog Please enter the second word: god dog is an anagram of god

Please enter the first word: bob Please enter the second word: bobs bob is NOT an anagram of bobs

Explanation / Answer

#include <stdio.h>
#include <string.h>

int main(){
   char buff[256], buff1[256];
   char second[256], second1[256];
   int arr[26] = {0};
   int i = 0, flag = 1;
   printf("Please enter the first word: ");
   scanf("%s", buff);
   strcpy(buff1, buff);
   for(i = 0; i < strlen(buff); ++i){
       if(buff[i] >= 97 && buff[i] <= 122)
           buff[i] = buff[i] - 32;
       arr[buff[i] - 'A']++;
   }
   printf("Please enter the second word: ");
   scanf("%s", second);
   strcpy(second1, second);
   for(i = 0; i < strlen(second); ++i){
       if(second[i] >= 97 && second[i] <= 122)
           second[i] = second[i] - 32;
       arr[second[i] - 'A']--;
   }
   for(i = 0; i < 26; ++i){
       if(arr[i] != 0){
           flag = 0;
           break;
       }
   }
   if(flag == 1){
       printf("%s is an anagram of %s", buff1, second1);
   }
   else{
       printf("%s is NOT an anagram of %s", buff1, second1);
   }
   return 0;
}

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