C++ I\'m having a syntax error at \" if (myclass[i].average >= 90) \" its says i
ID: 639099 • Letter: C
Question
C++
I'm having a syntax error at " if (myclass[i].average >= 90) " its says i is undeclared, eventhough its in the for statement. Anyone see what I did wrong?
void student::calculation()
{
for (int i = 0; i < numberofstudents; i++)
myclass[i].average = myclass[i].quiz1 * 10 * .125 + myclass[i].quiz2 * 10 * .125 + myclass[i].midterm *.25 + myclass[i].final * .50;
{
if (myclass[i].average >= 90)
myclass[i].grade = 'A';
else if (myclass[i].average >= 80)
myclass[i].grade = 'B';
else if (myclass[i].average >= 70)
myclass[i].grade = 'C';
else if (myclass[i].average >= 60)
myclass[i].grade = 'D';
else
myclass[i].grade = 'f';
}
}
Explanation / Answer
for (int i = 0; i < numberofstudents; i++)
myclass[i].average = myclass[i].quiz1 * 10 * .125 + myclass[i].quiz2 * 10 * .125 + myclass[i].midterm *.25 + myclass[i].final * .50;
{
if (myclass[i].average >= 90)
myclass[i].grade = 'A';
else if (myclass[i].average >= 80)
myclass[i].grade = 'B';
else if (myclass[i].average >= 70)
myclass[i].grade = 'C';
else if (myclass[i].average >= 60)
myclass[i].grade = 'D';
else
myclass[i].grade = 'f';
}
after for loop you kept
myclass[i].average = myclass[i].quiz1 * 10 * .125 + myclass[i].quiz2 * 10 * .125 + myclass[i].midterm *.25 + myclass[i].final * .50;
thats why....it was executing..next line it not enters into loop so thats why i is not defined
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