Question 5 1 pts If you measure the rate constant at two different temperatures,

Question

Question 5 1 pts If you measure the rate constant at two different temperatures, you can calculate the activation energy for a reaction using the formula: Where: T is temperature in Kelvin .R is the universal gas constant, 8.3145 Jmol K .Ea is the activation energy U mol .A is a proportionality constant termed the frequency factor k is the rate constant, measured at two temperatures For the gas phase transformation of A into B (A-B), the rate constant at 238 K is 0.147s and the rate constant at 468 K is 0.585 s. What is the activation energy for the reaction (J/mol)? Round your answer to the nearest whole number.

Explanation / Answer

Temperature T1 = 238 K

Rate constant k1 = 0.147 s-1

Temperature T2 = 468 K

Rae constant k2 = 0.585 s-1

Activation energy Ea =?

Gas constant R = 8.3145 J/mol·K

From the given equation

ln (k2/k1) = (-Ea/R) (1/T2 - 1/T1)

ln (0.585/0.147) = (-Ea/8.3145) (1/468 - 1/238)

1.3812 = Ea x 0.000248353

Ea = 5561 J/mol

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