age Learning-Google Chrome Assignment/takeCovalentActivity.do?locator-assignment

Question

age Learning-Google Chrome Assignment/takeCovalentActivity.do?locator-assignment-take&takeAssignmentSessionLocator; assignment-take Use the References to access important values if weeded for this question. For the following reaction, 0.313 moles of sulfur are mixed with 0.161 moles of carbon monoxide. sulfur(s) + carbon monoxide(g) ? sulfur dioxide(g) + carbon(s) What is the formula for the limiting reagent? What is the maximum amount of sulfur dioxide that can be produced? moles Submit Answer Retry Entire Group 9 more group altempts remaining ts 2req

Explanation / Answer

The Balanced equation is

S(s) + 2 CO(g) = SO2(g) + 2C(s)

From the stoichiometry of the reaction

1 mol S required = 2 mol CO

0.313 mol S required = 2 x 0.313 = 0.626 mol CO

But we have only 0.161 mol CO < 0.626 mol CO

Limiting reactant = CO

Maximum SO2 can be produced

= 1 mol SO2 x 0.161 mol CO / 2 mol CO

= 0.0805 mol SO2

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