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1. 0.5 moles of lithium chloride are dissolved in o.05 liters of water. What is

ID: 635904 • Letter: 1

Question

1. 0.5 moles of lithium chloride are dissolved in o.05 liters of water. What is the molarity of the solution? 2.0.25 grams of magnesium chloride are dissolved to make 50 militers of solution. What is the molarity of the solution? 3. 5.35 grams of sodium chloride are dissolved to make 150 milliliters of solution. What is the molarity of the solution? 4. 136 grams of barium sulfate are used to make a 2.5 M solution. How many liters of water are needed? 5. 62 grams of Zn(C2H302)4 are dissolved to make a 1.5 M solution. How many milliliters of water are needed? 6. What is the molality of a solution when 1.2 moles MgCl2 is stirred in 1000 grams of water? 7. How much water is needed to prepare a 50 molal solution using 0.50 moles of sodium chloride? 8. What is the molality when 0.15 mol SO2 is dissolved in 100 ml water? Remember 1 ml of water 1 gram of water)

Explanation / Answer

1. Molarity of solution = no. of moles of solute/volume of solution (L) = 0.5 mol/0.05 L =10 mol/L = 10 M

2. No. of moles of MgCl2 = mass of MgCl2/its molar mass = 0.25 g/(95 g/mol) = 0.00263 mol

Molarity of solution = 0.00263 mol/50*10-3 L = 0.0526 M

3. No. of moles of NaCl = 5.35 g/(58.5 g/mol) = 0.09145 mol

Molarity of solution = 0.09145 mol/150*10-3 L = 0.6097 M

4. No. of moles of BaSO4 = 136 g/(233.383 g/mol) = 0.58273 mol

2.5 mol/L = 0.58273 mol/volume of solution

i.e. Volume of solution = 0.58273 mol/(2.5 mol/L) = 0.2331 L