18. + -13 points SerCP11 11.P.027 Suppose 8.80 x 103 3 of energy are transferred

Question

18. + -13 points SerCP11 11.P.027 Suppose 8.80 x 103 3 of energy are transferred to 1.61 kg of ice at osC. The latent heat of fusion and specific heat f a 3.33 Jkg and c - 4186 (kgc) HINT (a) Calculate the energy (in ) required to melt all the ice into liquid water. (Enter your answer to at least three significant figures.) (b) How much energy (in J) remains to raise the temperature of the liquid water? (Enter your answer to at least three significant figures.) (c) Determine the final temperature of the liquid water in Celsius. oC

Explanation / Answer

Part a

Energy required to melt the ice at 0°C

= mass of ice x Latent heat of fusion

= 1.61 kg x 3.33 x 10^5 J/kg

= 536130 J

= 5.36*10^5 J

Part b

Energy remains to raise the temperature of the liquid

= total energy transfered - energy required for melting

= 8.80*10^5 - 5.36*10^5

= 3.44 x 10^5 J

Part c

Energy remains to raise the temperature of the liquid from 0 to T

= mass x Cp x (T2-T1)

3.44 x 10^5 J = 1.61 kg x 4186 J/kg-C x (T - 0)

T = 51.1 °C

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