A half-cell that consists of a copper wire in 1.00 M CuNO 3 solution is connecte

Question

A half-cell that consists of a copper wire in 1.00 M CuNO3 solution is connected by a salt bridge to a half cell containing a 1.00 M X(II) acetate solution and an electrode of metal X. The voltage of the cell is 0.74 V, with metal X as the positive electrode. Calculate the standard reduction potential for the X half-reaction. The standard reduction potential of the copper half-reaction is 0.52 V. (Hint, write the half-reactions and the overall chemical equation for the spontaneous reaction.) a.Calculate ?Go (in J) for 1 moles of electron(s) in each half-reaction and a standard potential of 0.16 V. b.Calculate ?Go (in J) for 2 moles of electron(s) in each half-reaction and a standard potential of (-0.47) V. c.Calculate Keq for 2 moles of electron(s) in each half-reaction and a standard potential of 0.12 V. d.Calculate Keq for 2 moles of electron(s) in each half-reaction and a standard potential of (-0.54) V.
A half-cell that consists of a copper wire in 1.00 M CuNO3 solution is connected by a salt bridge to a half cell containing a 1.00 M X(II) acetate solution and an electrode of metal X. The voltage of the cell is 0.74 V, with metal X as the positive electrode. Calculate the standard reduction potential for the X half-reaction. The standard reduction potential of the copper half-reaction is 0.52 V. (Hint, write the half-reactions and the overall chemical equation for the spontaneous reaction.) a.Calculate ?Go (in J) for 1 moles of electron(s) in each half-reaction and a standard potential of 0.16 V. b.Calculate ?Go (in J) for 2 moles of electron(s) in each half-reaction and a standard potential of (-0.47) V. c.Calculate Keq for 2 moles of electron(s) in each half-reaction and a standard potential of 0.12 V. d.Calculate Keq for 2 moles of electron(s) in each half-reaction and a standard potential of (-0.54) V.

Explanation / Answer

c.Calculate Keq for 2 moles of electron(s) in each half-reaction and a standard potential of 0.12 V.

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