A sodium hydroxide solution was prepared according to the procedure outlined in

Question

A sodium hydroxide solution was prepared according to the procedure outlined in this week's experiment. This sodium hydroxide solution was standardized by titration against exactly 10 mL of a0.2603M hydrochloric acid solution.

In three titrations, the volumes of the sodium hydroxide solution required to reach the equivalence point were8.27mL,8.42mL, and8.18mL.

1.)What is the molarity of your sodium hydroxide solution?

Molarity of NaOH =______M

This sodium hydroxide solution was then used to determine the amount of acetic acid in vinegar. Three titrations of the sodium hydroxide solution against exactly 5.0 mL of vinegar using phenolphthalein indicator required22.40mL,22.22mL, and22.48mL of the sodium hydroxide solution.

2.)What is the molarity of the acetic acid in vinegar?

Molarity of acetic acid in vinegar =_______M

Explanation / Answer

FOLLOW THIS

he molarity of NaOH is determined by saying


(Molarity x volume)NaOH = (Molarity x volume) acetic acid

therefore the answer is :
(M x 7.98ml) = (0.2838mol.dmx10ml)
(0.2838mol.dmx10ml)/7.98ml
= 0.3556390977 for [NaOH]

the 9.98ml is the average volume that reacted with HCl
use the same way to determine the next calculation

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