1.If 3.27 g of salicylic acid is reacted with 61 mL methanol, what is the maximu
ID: 630347 • Letter: 1
Question
1.If 3.27 g of salicylic acid is reacted with 61 mL methanol, what is the maximum mass of product (oil of wintergreen) that could be formed? The density of methanol is 0.791 g/mL. Give your answer in grams with 3 significant figures. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 2.Give your answer in grams with 3 significant figures. 3.Name the esters formed in Question 2. (Don't worry about the order. Ignore Water) ____, _____, ____ ,____. ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 3.Which of the following is an advantage of using squash preparations, as opposed to sectioned material? a.Whole cells can be observed b.Squashing allows all objects in a 3D cell to be seen on the same focal plane c.Both a) and b)Explanation / Answer
Salicylic acid = C7H6O3. We know it's molar mass is 138.12g/mol. So 3.27 grams is equal to 3.27/138.12 or 0.023675 mole. The balanced reaction is: C7H6O3 + CH3OH ------> C8H8O3(this is oil of wintergreen, an ester) + H2O 61 ml. of methanol has a density of 0.791 gm/ml and so the mass mass is 48.19 grams. THe molar mass is 32.04, so that is 1.504 moles. We realize salicylic acid is the limitingreactant. We can use stoichiometric ratios .023675 mol * 1mol of C8H4O3/1 mol of C7H603 = .023675 moles of oil of wintergreen. This is the maximum # of moles that will be produced. The molar mass of the product is 152.15 grams/mol. So .023675mol * 152.15 g/mol = 3.6021 grams of oil of wintergreen. That is 3.60 gm. to 3 significant figures. Ester formed is methylsalicylate(C8H8O3)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.