5.) (10 pts.) Suppose that an X - linked locus is segregating two alleles, A and

Question

5.) (10 pts.) Suppose that an X - linked locus is segregating two alleles, A and a, and let pf(0) and pm (0) be the frequencies of A in the current generation of females and males, respectively. Assuming that (i) the population is infinite; (ii) males and females are equally abundant; (iii) mating is random; (iv) generations are non - overlapping; (y) the alleles are selectively neutral; and (vi) there is no mutation, find (a) the frequencies pf(1) and pm(1) of A in the next generation of females and males; (b) the limiting values of pf(t) and pm(t) as t ? > infinity. Hint: Investigate the dynamics of the overall frequency of A in the population. (c) What will the limiting frequencies be if we consider a finite population satisfying assumptions (ii) - (vi)?

Explanation / Answer

Based on the given data,

Males are hemizygous for X-linked genes and males have a single copy of these gens, so for X-linked genes in males, the genotypic frequencies are equal to allelic frequencies.

However, females follow normal HW exceptions: fA/A = P2, fA/a = 2pq, and fa/a = q2. In the given data, it is stated that male and female population is equal, so initial genotypic frequencies 0.5 for both males and females.

Here, the frequency of

(a)
Thus, the genotype frequencies after one generation are:

Hence, allelic frequency of males is:

q2 = 0.25 = q(m)

So, p+q = 1

p = 1- q

1-0.25 = 0.75

Therefore,

Related Questions

Navigate

• Browse (All)
• Browse 5
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.