Solution flasks: A: 5.00 mL of 3 M HCl + 5.00 mL of EtAc B: 5.00 mL of 3 M HCl +

Question

Solution flasks:

A: 5.00 mL of 3 M HCl + 5.00 mL of EtAc

B: 5.00 mL of 3 M HCl + 4.00 mL of EtAc + 1.00 mL of distilled water

C: 5.00 mL of 3 M HCl + 3.00 mL of EtAc + 2.00 mL of distilled water

Question 1:

In throry, which K(eq) obtained should be the biggest for these three solution? WHY?

Question 2:

IF a student didn't remove a small amount of water found in his test tube when he made the solution C, the equilibrium constant he obtained would be _______ (higher, lower or no change) in comparison with what it should be? WHY?

(do NOT try to ask if you are not an expert!! Thanks)

Explanation / Answer

1)

Solution A should have the highest Keq.

This is because the solutes are the least diluted ( and thus have the highest concentrations) in solution A

2)

It would be lower.

If the student did not remove the water, that would result in the solution being more dilute. So the concentrations of the solutes are lower and thus the Keq is lower.

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