4. The radioactive nuclide 100Tc decays to form the stable nuclide 100Mo. a) The

Question

4. The radioactive nuclide 100Tc decays to form the stable nuclide 100Mo. a) There are two possible pathways for this decay. Write a balanced equation for each. b) Only one of these pathways is ever observed. Calculate the energy released by both pathways, and explain why only one is observed. Masses: 100 Tc: 99.907657 amu 100Mo: 99.90748 amu e

Explanation / Answer

Two possible decays are beta+ decay and electron capture decays, 100Tc ----> 100Mo + e+ + v , 100Tc + e- ----> 100Mo + v , where v - neutrino, e+ is positoron , e- is electron, b) in process of beta + decay E = (mass difference of two main nuclides) x (931.5)-2(rest mass energy of elctron ) , = (99.907657-99.90748)(931.5 ) -2(0.511) = -ve , hence this process is not possible. energy released in electron capture rxn = (99.907657+0.0005486-99.90748)x931.5 = 0.676 MeV

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