1. 2C8H18+25O2------>16CO2+18H2O how many moles of CO2 are emitted into the atom
ID: 626233 • Letter: 1
Question
1. 2C8H18+25O2------>16CO2+18H2O how many moles of CO2 are emitted into the atomosphere when 17,6 g of C8H18 is burned 2. complete this reaction to show how pyridine, C5H6NH acts as a Bronsted-Lowry base in water C5H5N+H2O------C5H6NH+ +OH- 3.calculate either H3O+ or OH- for the solutions below at 25 degrees C. OH- =2.87x10 (-7) M H3O- _______M H3O+=8.33x10 (-9) M OH- =_________M H3O+=0.000623 M OH- = _________M PH=1.0x10(1) H3O+ =_________M 4. What are the concentrations of H3O+ and OH- in oranges that have a PH of 3..80? H3O+ = _________M OH- = __________M 5. Classify each solution as acidic, basic or neutral in an aqueous solution of 25 degrees C. Ph=2.65 H+ =9.1x10(-3) OH- =9.7x10(-2) Ph=9.30 H+ =7.3x10(-11) OH- =2.3x10(-13) PH=7.0 H+ =1.0x10(-7)Explanation / Answer
for 25 moles of O2 -> 16 moles of CO2 is produced
for 1 moles of O2 -> 16/25 moles of CO2 is produced
so for 4.06 moles of O2 -> 16/25 * 4.06 moles of CO2 is produced
C5H5N + H+ ---> C5H5NH+
C5H5H +H2O---> C5H5NH+ + OH-
Proton acceptor.
HClO4 -----------------> H+ + ClO4- (H+ = H3O+) Since HClO4 dissociates 100 percent, the concentration of H+ and ClO- will both be 0.155 mol/L
So you have the concentration of [H3O+] = [ClO4-] = 0.155 mol/L
The pH of this is -log(0.155) = 0.81
pH + pOH = 14
So the pOH = 14 - 0.81 = 13.19
[OH-] = 10^-13.19 = 6.45 x 10^-14
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