Learning Goal: To determine equilibrium concentrations from initial conditions.

Question

Learning Goal: To determine equilibrium concentrations from initial conditions. The reversible reaction XY(aq) double arrow X(aq)+Y(aq) Calculating equilibrium concentrations when the net reaction proceeds forward Consider mixture B, which will cause the net reaction to proceed forward. The change in concentration, x, is negative for the reactants because they are consumed and positive for the products because they are produced. Based on a Kc value of 0.250 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse. The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed. Based on a Kc value of 0.250 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically.

Explanation / Answer

kc=[X][Y]/[XY] 0.250=(.1+x)(.1+x)/(.5-x) 0.125--0.25x=0.01+0.2x+x^2 x^2+0.45x-0.115=0 x=0.189,-0.63 cosider x=.189 [xy]=0.5-0.189=0.311 [x]=[y]=0.289 partc) 0.250=(.3+x)(.3+x)/(.2-x) solve for x and put in conc. term we get conc. xy ,x, y simmilar uper part

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