47. (10 points) In a wild population of fruit flies, 36% have long wings, 48% ha

Question

47. (10 points) In a wild population of fruit flies, 36% have long wings, 48% have medium wings, and 6.25% have short wings. You find that flies with long wings are GG, medium wings are Gg, and short wings are ge. a) What are your allele frequencies (p is the frequency of G) and is your population in Hardy-Weinberg equilibrium? b) You move the fruit flies into the lab and after a few generations, you find that the population now has fewer short winged individuals. The new frequencies are 49% long winged, 42% medium winged, and 9% short winged. Assuming that the lab population has stabilized to Hardy-Weinberg equilibrium, What is Ap compared to the wild population? d) Initially in the population, the fitness of GG flies in the lab is 1, Gg flies is 0.643 and gg flies is 0.413, what is the average excess of fitness for alleles G and g in the lab? e) For each genotype, would the wild type population have higher or lower fitness than the lab population?

Explanation / Answer

The given frequencies are genotype frequencies-

GG-36%

Gg-48%

gg - 6.25% Taking as 7%

Taking total population as 100, we can take the above numbers are the number of individuals having that particular genotype.

The total is 91.

The frequency of G allele is 2 x 36 + 48 / Total numb of alleles(182)

=120/182

= 0.65

The frequency of the g allele will be:

= 48 + 2x 7/182

= 62/182

=0.34

since p + q = 1 and 0.65 + 0.34 = 0.99 the population is in hardy weinberg equilibrium

we cannot answer more than one question in a single post according to chegg rules.

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.