Please choose the letter that best answers the question. Please provide explanat
ID: 62494 • Letter: P
Question
Please choose the letter that best answers the question. Please provide explanation 18. Hexokinase has a KM of 0.05 mM for D-glucose and a KM of 1.5 mM for D-fructose. From this we can e conclude that: a. The Vmax of Hexokinase with D-fructose is 3x the Vmax with D-glucose. b) Hexokinase has a greater affinity for D-glucose than for D-fructose. D-glucose is a better substrate for Hexokinase than D-fructose. d. It takes less D-glucose for the reaction to reach ½ Vmax than D-fructose. e. Answers b. c., and d. Answers b. and c.Explanation / Answer
High Km value means low affinity for substrate and vice-versa. So, in the above qs, hexokinase has low Km value for D-glucose; i.e. high substrate affinity for glucose than fructose(b option is correct.)
Therefore, D-glucose is a better substrate for hexokinase than D-fructose (c option is also correct).
d option is also correct. Km is that substrate concentration at which Vmax is half.
So, overall the correct option will be e.
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