A soft drink was bottled with a CO2 partial pressure of 5.00 atm at 25 degrees C

Question

A soft drink was bottled with a CO2 partial pressure of 5.00 atm at 25 degrees C. After the bottle had been open for a while, the CO2 partial pressure decreased to 1.50 x 10^-5 atm. What is the concentration of the CO2 in the opened bottle if the Henry's law constant for CO2 at 25 degrees C is 3.10 x 10^-2 mol/L-atm? I need step by step to understand how to figure this out...Having a hard time getting it! Thanks A) 2.15 x 106 M B) 1.94 x 10^-5 M C) 4.65 x 10^-7 M D) 5.17 x 104 M Just by looking, I'm guessing it's either B) or C)

Explanation / Answer

P = KHC

1.5*10^-5 = 3.1*10^-2*C

C = (1.5/3.1)*10^-3 M

C = 4.83*10^-4 M

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.