Write the Complete Ionic Equation for the reaction between Sodium Bicarbonate an

Question

Write the Complete Ionic Equation for the reaction between Sodium Bicarbonate and Hydrochloric Acid Write the Net Ionic Equation for the reaction between Sodium Bicarbonate and Hydrochloric Acid

Explanation / Answer

Acid reacting with a carbonate is one of those reactions you just learn produces a gas. In determining the net ionic reaction, first consider which of the reactants and products is soluble. Na2CO3: dissociates (it is a sodium salt) HCl: dissociates (it is a strong acid) The reaction is a double replacement reaction, so the nominal molecular equation is as follows: Na2CO3 + 2 HCl --> 2 NaCl + H2CO3 the last of these species, carbonic acid, is not stable in a water solution in high concentrations, so it decomposes to form carbon dioxide and water. H2CO3 --> H2O + CO2 As such, the "molecular" equation for the reaction is Na2CO3 + 2 HCl --> 2 NaCl + H2O + CO2 Now consider which of the products is soluble (as in it dissociates in water.) The only one is NaCl! So let's write the total ionic reaction. 2 Na+(aq) + CO3-2(aq) + 2 H+(aq) + 2 Cl-(aq) --> 2 Na+(aq) + 2 Cl-(aq) + H2O(l) + CO2(g) The species that occur on both sides of the arrow unchanged in the total ionic equation are Na+(aq) and Cl-(aq). We can remove them as they are spectator ions. The net ionic equation is then 2 H+(aq) + CO3-2(aq) --> H2O(l) + CO2(g) Don't get confused if things are forming liquid water or a gas such as CO2, NO or SO2. You can approach the problem the same way you can any net ionic reaction for a double replacement reaction.

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